cleanup: Use jsoup xml escaper
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@@ -18,6 +18,8 @@ package com.hippo.yorozuya;
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import android.text.TextUtils;
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import org.jsoup.parser.Parser;
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import java.util.ArrayList;
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import java.util.Arrays;
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import java.util.List;
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@@ -30,25 +32,6 @@ public final class StringUtils {
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'\u00A0', // NO-BREAK SPACE
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'\u3000', // IDEOGRAPHIC SPACE
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};
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private static final String[] ESCAPE_CHARATER_LIST = {
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"&",
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"<",
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">",
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""",
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"'",
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"×",
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" "
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};
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private static final String[] UNESCAPE_CHARATER_LIST = {
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"&",
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"<",
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">",
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"\"",
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"'",
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"×",
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" "
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};
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private StringUtils() {
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}
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@@ -57,7 +40,7 @@ public final class StringUtils {
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* Unescape xml. It do not work perfectly.
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*/
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public static String unescapeXml(String str) {
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return replaceEach(str, ESCAPE_CHARATER_LIST, UNESCAPE_CHARATER_LIST);
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return Parser.unescapeEntities(str, true);
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}
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/**
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@@ -141,218 +124,6 @@ public final class StringUtils {
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return buf.toString();
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}
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/**
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* <p>
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* Replaces all occurrences of Strings within another String.
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* </p>
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*
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* <p>
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* A {@code null} reference passed to this method is a no-op, or if
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* any "search string" or "string to replace" is null, that replace will be
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* ignored. This will not repeat. For repeating replaces, call the
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* overloaded method.
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* </p>
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*
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* <pre>
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* StringUtils.replaceEach(null, *, *) = null
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* StringUtils.replaceEach("", *, *) = ""
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* StringUtils.replaceEach("aba", null, null) = "aba"
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* StringUtils.replaceEach("aba", new String[0], null) = "aba"
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* StringUtils.replaceEach("aba", null, new String[0]) = "aba"
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* StringUtils.replaceEach("aba", new String[]{"a"}, null) = "aba"
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* StringUtils.replaceEach("aba", new String[]{"a"}, new String[]{""}) = "b"
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* StringUtils.replaceEach("aba", new String[]{null}, new String[]{"a"}) = "aba"
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* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"w", "t"}) = "wcte"
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* (example of how it does not repeat)
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* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"d", "t"}) = "dcte"
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* </pre>
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*
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* @param text text to search and replace in, no-op if null
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* @param searchList the Strings to search for, no-op if null
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* @param replacementList the Strings to replace them with, no-op if null
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* @return the text with any replacements processed, {@code null} if
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* null String input
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* @throws IllegalArgumentException if the lengths of the arrays are not the same (null is ok,
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* and/or size 0)
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*/
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// Get from org.apache.commons.lang3.StringUtils
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public static String replaceEach(final String text, final String[] searchList,
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final String[] replacementList) {
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return replaceEach(text, searchList, replacementList, false, 0);
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}
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/**
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* <p>
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* Replaces all occurrences of Strings within another String.
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* </p>
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*
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* <p>
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* A {@code null} reference passed to this method is a no-op, or if
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* any "search string" or "string to replace" is null, that replace will be
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* ignored.
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* </p>
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*
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* <pre>
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* StringUtils.replaceEach(null, *, *, *) = null
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* StringUtils.replaceEach("", *, *, *) = ""
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* StringUtils.replaceEach("aba", null, null, *) = "aba"
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* StringUtils.replaceEach("aba", new String[0], null, *) = "aba"
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* StringUtils.replaceEach("aba", null, new String[0], *) = "aba"
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* StringUtils.replaceEach("aba", new String[]{"a"}, null, *) = "aba"
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* StringUtils.replaceEach("aba", new String[]{"a"}, new String[]{""}, *) = "b"
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* StringUtils.replaceEach("aba", new String[]{null}, new String[]{"a"}, *) = "aba"
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* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"w", "t"}, *) = "wcte"
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* (example of how it repeats)
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* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"d", "t"}, false) = "dcte"
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* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"d", "t"}, true) = "tcte"
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* StringUtils.replaceEach("abcde", new String[]{"ab", "d"}, new String[]{"d", "ab"}, *) = IllegalStateException
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* </pre>
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*
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* @param text text to search and replace in, no-op if null
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* @param searchList the Strings to search for, no-op if null
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* @param replacementList the Strings to replace them with, no-op if null
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* @param repeat if true, then replace repeatedly
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* until there are no more possible replacements or timeToLive < 0
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* @param timeToLive if less than 0 then there is a circular reference and endless
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* loop
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* @return the text with any replacements processed, {@code null} if
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* null String input
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* @throws IllegalStateException if the search is repeating and there is an endless loop due
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* to outputs of one being inputs to another
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* @throws IllegalArgumentException if the lengths of the arrays are not the same (null is ok,
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* and/or size 0)
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*/
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// Get from org.apache.commons.lang3.StringUtils
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private static String replaceEach(
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final String text, final String[] searchList,
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final String[] replacementList, final boolean repeat,
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final int timeToLive) {
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// mchyzer Performance note: This creates very few new objects (one major goal)
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// let me know if there are performance requests, we can create a harness to measure
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if (text == null || TextUtils.isEmpty(text) || searchList == null ||
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searchList.length == 0 || replacementList == null || replacementList.length == 0) {
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return text;
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}
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// if recursing, this shouldn't be less than 0
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if (timeToLive < 0) {
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throw new IllegalStateException("Aborting to protect against StackOverflowError - " +
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"output of one loop is the input of another");
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}
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final int searchLength = searchList.length;
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final int replacementLength = replacementList.length;
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// make sure lengths are ok, these need to be equal
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if (searchLength != replacementLength) {
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throw new IllegalArgumentException("Search and Replace array lengths don't match: "
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+ searchLength
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+ " vs "
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+ replacementLength);
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}
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// keep track of which still have matches
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final boolean[] noMoreMatchesForReplIndex = new boolean[searchLength];
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// index on index that the match was found
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int textIndex = -1;
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int replaceIndex = -1;
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int tempIndex = -1;
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// index of replace array that will replace the search string found
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// NOTE: logic duplicated below START
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for (int i = 0; i < searchLength; i++) {
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if (noMoreMatchesForReplIndex[i] || searchList[i] == null ||
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TextUtils.isEmpty(searchList[i]) || replacementList[i] == null) {
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continue;
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}
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tempIndex = text.indexOf(searchList[i]);
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// see if we need to keep searching for this
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if (tempIndex == -1) {
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noMoreMatchesForReplIndex[i] = true;
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} else {
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if (textIndex == -1 || tempIndex < textIndex) {
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textIndex = tempIndex;
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replaceIndex = i;
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}
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}
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}
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// NOTE: logic mostly below END
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// no search strings found, we are done
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if (textIndex == -1) {
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return text;
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}
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int start = 0;
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// get a good guess on the size of the result buffer so it doesn't have to double if it goes over a bit
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int increase = 0;
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// count the replacement text elements that are larger than their corresponding text being replaced
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for (int i = 0; i < searchList.length; i++) {
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if (searchList[i] == null || replacementList[i] == null) {
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continue;
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}
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final int greater = replacementList[i].length() - searchList[i].length();
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if (greater > 0) {
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increase += 3 * greater; // assume 3 matches
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}
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}
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// have upper-bound at 20% increase, then let Java take over
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increase = Math.min(increase, text.length() / 5);
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final StringBuilder buf = new StringBuilder(text.length() + increase);
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while (textIndex != -1) {
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for (int i = start; i < textIndex; i++) {
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buf.append(text.charAt(i));
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}
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buf.append(replacementList[replaceIndex]);
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start = textIndex + searchList[replaceIndex].length();
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textIndex = -1;
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replaceIndex = -1;
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tempIndex = -1;
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// find the next earliest match
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// NOTE: logic mostly duplicated above START
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for (int i = 0; i < searchLength; i++) {
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if (noMoreMatchesForReplIndex[i] || searchList[i] == null ||
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TextUtils.isEmpty(searchList[i]) || replacementList[i] == null) {
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continue;
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}
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tempIndex = text.indexOf(searchList[i], start);
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// see if we need to keep searching for this
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if (tempIndex == -1) {
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noMoreMatchesForReplIndex[i] = true;
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} else {
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if (textIndex == -1 || tempIndex < textIndex) {
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textIndex = tempIndex;
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replaceIndex = i;
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}
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}
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}
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// NOTE: logic duplicated above END
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}
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final int textLength = text.length();
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for (int i = start; i < textLength; i++) {
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buf.append(text.charAt(i));
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}
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final String result = buf.toString();
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if (!repeat) {
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return result;
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}
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return replaceEach(result, searchList, replacementList, repeat, timeToLive - 1);
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}
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public static boolean endsWith(String string, String[] suffixs) {
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for (int i = 0, n = suffixs.length; i < n; i++) {
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if (string.endsWith(suffixs[i])) {
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@@ -464,38 +235,6 @@ public final class StringUtils {
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return null == str ? 0 : str.length();
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}
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/**
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* <p>Counts how many times the char appears in the given string.</p>
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*
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* <p>A {@code null} or empty ("") String input returns {@code 0}.</p>
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*
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* <pre>
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* StringUtils.countMatches(null, *) = 0
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* StringUtils.countMatches("", *) = 0
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* StringUtils.countMatches("abba", 0) = 0
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* StringUtils.countMatches("abba", 'a') = 2
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* StringUtils.countMatches("abba", 'b') = 2
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* StringUtils.countMatches("abba", 'x') = 0
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* </pre>
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*
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* @param str the CharSequence to check, may be null
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* @param ch the char to count
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* @return the number of occurrences, 0 if the CharSequence is {@code null}
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*/
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public static int countMatches(final CharSequence str, final char ch) {
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if (TextUtils.isEmpty(str)) {
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return 0;
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}
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int count = 0;
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// We could also call str.toCharArray() for faster look ups but that would generate more garbage.
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for (int i = 0; i < str.length(); i++) {
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if (ch == str.charAt(i)) {
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count++;
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}
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}
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return count;
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}
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/**
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* All null or empty, or all not
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*/
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@@ -1,5 +1,7 @@
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package com.hippo.yorozuya
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import org.jsoup.parser.Parser
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fun String.unescapeXml(): String {
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return StringUtils.unescapeXml(this)
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return Parser.unescapeEntities(this, true)
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}
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