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# Review 8-1
* Hajin Ju, 2024062806
## Problem 1
Fill in the blanks in the following assembly-line scheduling example.
### Solution 1
![](/assets/R8-1_1.png)
**table $s$**
| $s$ | 1 | 2 | 3 | 4 | 5 | 6 |
| --- | --- | --- | --- | --- | --- | --- |
| 1 | 9 | 18 | 20 | 24 | 32 | 35 |
| 2 | 12 | 16 | 22 | 25 | 30 | 37 |
**table $l$**
| $l$ | 1 | 2 | 3 | 4 | 5 | 6 |
| --- | --- | --- | --- | --- | --- | --- |
| 1 | - | 1 | 2 | 1 | 1 | 2 |
| 2 | - | 1 | 2 | 1 | 2 | 2 |
$$\begin{align*}s^* &= 38\\l^* &= 1\end{align*}$$
## Problem 2
Fill in the blanks in the following pseudocode for assembly-line scheduling
### Solution 2
```python
FASTEST-WAY(a, t, e, x, n)
s[1][1] = e[1] + a[1][1]
s[2][1] = e[2] + a[2][1]
for j = 2 to n
do
if s[1][j-1] + a[1][j] <= s[2][j-1] + t[2][j-1] + a[1][j]
then s[1][j] = s[1][j-1] + a[1][j]
l[1][j] = 1
else s[1][j] = s[2][j-1] + t[2][j-1] + a[1][j]
l[1][j] = 2
if s[2][j-1] <= s[1][j-1] + t[1][j-1]
then s[2][j] = s[2][j-1] + a[2][j]
l[2][j] = 2
else s[2][j] = s[1][j-1] + t[1][j-1] + a[2][j]
l[2][j] = 1
if s[1][n] + x[1] <= s[2][n] + x[2]
then s* = s[1][n] + x[1]
l* = 1
else s* = s[2][n] + x[2]
l* = 2
```