164 lines
40 KiB
HTML
164 lines
40 KiB
HTML
<!DOCTYPE html>
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<html lang="ko">
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<head>
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<meta charset="UTF-8" />
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<meta name="viewport" content="width=device-width, initial-scale=1.0" />
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<title>BOJ 2565 - Offline</title>
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<style>
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:root {
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--bg: #fafaf8;
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--paper: #ffffff;
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--ink: #1e1f24;
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--muted: #6a6d75;
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--line: #d8dce3;
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--accent: #0d6e6e;
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--code-bg: #f4f6fb;
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}
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* { box-sizing: border-box; }
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body {
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margin: 0;
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background:
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radial-gradient(circle at 15% 0%, #f0efe9 0%, transparent 42%),
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radial-gradient(circle at 85% 20%, #e7f1f2 0%, transparent 38%),
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var(--bg);
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color: var(--ink);
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font-family: "Noto Sans KR", "Pretendard", "Apple SD Gothic Neo", sans-serif;
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line-height: 1.65;
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}
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main {
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max-width: 980px;
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margin: 0 auto;
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padding: 24px 16px 56px;
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}
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.header {
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background: var(--paper);
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border: 1px solid var(--line);
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border-radius: 14px;
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padding: 18px 20px;
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margin-bottom: 18px;
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}
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.header h1 { margin: 0 0 6px; font-size: 1.5rem; }
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.header p { margin: 0; color: var(--muted); font-size: 0.95rem; }
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.header a { color: var(--accent); text-decoration: none; }
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.section {
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background: var(--paper);
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border: 1px solid var(--line);
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border-radius: 14px;
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padding: 16px 18px;
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margin-bottom: 14px;
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overflow-x: auto;
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}
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h2 {
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margin: 0 0 10px;
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font-size: 1.05rem;
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color: var(--accent);
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border-bottom: 1px solid var(--line);
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padding-bottom: 8px;
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}
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pre, code {
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font-family: "JetBrains Mono", "Fira Code", monospace;
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background: var(--code-bg);
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}
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pre {
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padding: 12px;
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border-radius: 10px;
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border: 1px solid #e7ebf2;
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overflow: auto;
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}
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blockquote {
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margin: 14px 0;
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padding: 16px 16px 14px 22px;
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border-left: 4px solid var(--accent);
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border-radius: 10px;
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background: linear-gradient(90deg, #eef8f8 0%, #f9fdfd 100%);
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color: #24313a;
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font-weight: 600;
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position: relative;
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}
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blockquote::before {
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content: "“";
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position: absolute;
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left: 8px;
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top: 2px;
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font-size: 1.35rem;
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line-height: 1;
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color: #0b5f5f;
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opacity: 0.7;
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}
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blockquote > :first-child { margin-top: 0; }
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blockquote > :last-child { margin-bottom: 0; }
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q {
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color: #114f50;
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font-weight: 700;
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background: #edf8f8;
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border-radius: 6px;
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padding: 0 4px;
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}
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.math-inline math {
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font-size: 1em;
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vertical-align: middle;
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}
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.math-block {
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margin: 10px 0;
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padding: 8px 10px;
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overflow-x: auto;
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background: #f8fbff;
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border: 1px solid #e2ecf8;
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border-radius: 8px;
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}
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.math-block math {
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font-size: 1.04em;
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display: block;
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}
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table { border-collapse: collapse; width: 100%; }
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th, td { border: 1px solid var(--line); padding: 6px 8px; }
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img { max-width: 100%; height: auto; }
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</style>
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</head>
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<body>
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<main>
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<header class="header">
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<h1>전깃줄</h1>
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</header>
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<article class="section">
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<h2>문제</h2>
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<p>두 전봇대 A와 B 사이에 하나 둘씩 전깃줄을 추가하다 보니 전깃줄이 서로 교차하는 경우가 발생하였다. 합선의 위험이 있어 이들 중 몇 개의 전깃줄을 없애 전깃줄이 교차하지 않도록 만들려고 한다.</p>
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<p>예를 들어, < 그림 1 >과 같이 전깃줄이 연결되어 있는 경우 A의 1번 위치와 B의 8번 위치를 잇는 전깃줄, A의 3번 위치와 B의 9번 위치를 잇는 전깃줄, A의 4번 위치와 B의 1번 위치를 잇는 전깃줄을 없애면 남아있는 모든 전깃줄이 서로 교차하지 않게 된다.</p>
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style="width: 183px; height: 288px;" /></p>
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<p style="text-align: center;">< 그림 1 ></p>
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<p>전깃줄이 전봇대에 연결되는 위치는 전봇대 위에서부터 차례대로 번호가 매겨진다. 전깃줄의 개수와 전깃줄들이 두 전봇대에 연결되는 위치의 번호가 주어질 때, 남아있는 모든 전깃줄이 서로 교차하지 않게 하기 위해 없애야 하는 전깃줄의 최소 개수를 구하는 프로그램을 작성하시오.</p>
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</article>
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<article class="section">
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<h2>입력</h2>
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<p>첫째 줄에는 두 전봇대 사이의 전깃줄의 개수가 주어진다. 전깃줄의 개수는 100 이하의 자연수이다. 둘째 줄부터 한 줄에 하나씩 전깃줄이 A전봇대와 연결되는 위치의 번호와 B전봇대와 연결되는 위치의 번호가 차례로 주어진다. 위치의 번호는 500 이하의 자연수이고, 같은 위치에 두 개 이상의 전깃줄이 연결될 수 없다.</p>
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</article>
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<article class="section">
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<h2>출력</h2>
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<p>첫째 줄에 남아있는 모든 전깃줄이 서로 교차하지 않게 하기 위해 없애야 하는 전깃줄의 최소 개수를 출력한다.</p>
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</article>
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<article class="section">
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<h2>예제 입력 1 복사</h2>
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<pre class="sampledata" id="sample-input-1">8
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1 8
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3 9
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2 2
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4 1
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6 4
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10 10
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9 7
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7 6
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</pre>
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</article>
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<article class="section">
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<h2>예제 출력 1 복사</h2>
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<pre class="sampledata" id="sample-output-1">3
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</pre>
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</article>
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</main>
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</body>
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</html>
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